4[1-3(r+2)]+2r=0

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Solution for 4[1-3(r+2)]+2r=0 equation:


Simplifying
4[1 + -3(r + 2)] + 2r = 0

Reorder the terms:
4[1 + -3(2 + r)] + 2r = 0
4[1 + (2 * -3 + r * -3)] + 2r = 0
4[1 + (-6 + -3r)] + 2r = 0

Combine like terms: 1 + -6 = -5
4[-5 + -3r] + 2r = 0
[-5 * 4 + -3r * 4] + 2r = 0
[-20 + -12r] + 2r = 0

Combine like terms: -12r + 2r = -10r
-20 + -10r = 0

Solving
-20 + -10r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -10r = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -10r = 0 + 20
-10r = 0 + 20

Combine like terms: 0 + 20 = 20
-10r = 20

Divide each side by '-10'.
r = -2

Simplifying
r = -2

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